In computing, the producer–consumer problem(also known a s the bounded-buffer problem) is a classic example of a multi-process synchronization problem. The problem describes two processes, the producer and the consumer, who share a common, fixed-size buffer used as a queue. The producer's job is to generate a piece of data, put it into the buffer and start again. At the same time, the consumer is consuming the data (i.e., removing it from the buffer) one piece at a time. The problem is to make sure that the producer won't try to add data into the buffer if it's full and that the consumer won't try to remove data from an empty buffer.
The solution for the producer is to either go to sleep or discard data if the buffer is full. The next time the consumer removes an item from the buffer, it notifies the producer, who starts to fill the buffer again. In the same way, the consumer can go to sleep if it finds the buffer to be empty. The next time the producer puts data into the buffer, it wakes up the sleeping consumer. The solution can be reached by means of inter-process communication, typically using semaphores. An inadequate solution could result in a deadlock where both processes are waiting to be awakened. The problem can also be generalized to have multiple producers and consumers.
import java.util.Vector;
import java.util.logging.Level;
import java.util.logging.Logger;
public class ProducerConsumerSolution {
public static void main(String args[]) {
Vector sharedQueue = new Vector();
int size = 5;
Thread prodThread = new Thread(new Producer(sharedQueue, size), "Producer");
Thread consThread = new Thread(new Consumer(sharedQueue, size), "Consumer");
prodThread.start();
consThread.start();
}
}
class Producer implements Runnable {
private final Vector sharedQueue;
private final int SIZE;
public Producer(Vector sharedQueue, int size) {
this.sharedQueue = sharedQueue;
this.SIZE = size;
}
@Override
public void run() {
for (int i = 0; i < 7; i++) {
System.out.println("Produced: " + i);
try {
produce(i);
} catch (InterruptedException ex) {
Logger.getLogger(Producer.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
private void produce(int i) throws InterruptedException {
//wait if queue is full
while (sharedQueue.size() == SIZE) {
synchronized (sharedQueue) {
System.out.println("Queue is full " + Thread.currentThread().getName()
+ " is waiting , size: " + sharedQueue.size());
sharedQueue.wait();
}
}
//producing element and notify consumers
synchronized (sharedQueue) {
sharedQueue.add(i);
sharedQueue.notifyAll();
}
}
}
class Consumer implements Runnable {
private final Vector sharedQueue;
private final int SIZE;
public Consumer(Vector sharedQueue, int size) {
this.sharedQueue = sharedQueue;
this.SIZE = size;
}
@Override
public void run() {
while (true) {
try {
System.out.println("Consumed: " + consume());
Thread.sleep(50);
} catch (InterruptedException ex) {
Logger.getLogger(Consumer.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
private int consume() throws InterruptedException {
//wait if queue is empty
while (sharedQueue.isEmpty()) {
synchronized (sharedQueue) {
System.out.println("Queue is empty " + Thread.currentThread().getName()
+ " is waiting , size: " + sharedQueue.size());
sharedQueue.wait();
}
}
//Otherwise consume element and notify waiting producer
synchronized (sharedQueue) {
sharedQueue.notifyAll();
return (Integer) sharedQueue.remove(0);
}
}
}
Output:
Produced: 0
Queue is empty Consumer is waiting , size: 0
Produced: 1
Consumed: 0
Produced: 2
Produced: 3
Produced: 4
Produced: 5
Produced: 6
Queue is full Producer is waiting , size: 5
Read More
Java 7 featuresHow to Reset Arraylist In Java
How HashMap Work in Java
Why wait (), notify () and notifyAll () must be called from synchronized block or method in Java
XPath to locate Information in XML
Internals of Garbage Collector
Reference Type in Java
Different Ways to Create ObjectClass Loaders in Java
Producer Consumer Problem
Why String is Final in Java
Singleton Class using Enum
Exceptional Handling in Java
No comments:
Post a Comment